The concentration feed liquor should be
calculated, so that at the correct rate of addition, the feed liquor
replaces the chemical taken out of the saturator by the fabric.
Let Exit Mangle Expression = Eo
Entry Mangle Expression = E1
Percentage chemical on the fabric = Y
Thus Y = (Saturator concentration (K1)
X Effective pick up) / 1000
Y = {K1[Eo - E1]
+ [E1 X F]}
/
1000
---- (3)
The volume change (V) per minute in the
saturator is:
V = {W X [Eo - E1]}
/ SG X 100 = W(Eo - E1)
/ 100 liters per minute, assuming SG( Specific Gravity) = 1 and the
weight (W) chemical used per minute is:
W = (W X Y) / 100 kg per minute = (W X Y) X 1000/100
where the X denotes the multiplication sign
throughout this page.
The feed liquor should add this amount, W,
in the volume V, to maintain concentration and volume of saturator. This
is the feed liquor concentration K2.
K2 =
W / V = {(W X Y) / 100} X { (1000 X 100) / W[Eo - E1]
= 1000Y/ [Eo - E1]
grams/liter
Y = K2 [Eo - E1]
/
1000
--- (4)
Equating 3 and 4, we have
K2 = {K1[Eo - E1]
+ [E1 X F]}
/ [Eo - E1] |
